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Is there a mathematician in the house?
Jj
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A RW feature states: 'A 12-stone man running at nine minutes/mile burns 500 calories in around 35 minutes.'
Can anyone do the maths on how many calories an 11-stone woman running at 12 minutes/mile burns in the same time?
Can anyone do the maths on how many calories an 11-stone woman running at 12 minutes/mile burns in the same time?
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However, it is more complex when looking to convert the rate when another speed is considered. As a general rule of thumb, you'll use 100 calories/ mile, plus or minus 15%.
For the 12 stone man running approximate 9 min/mile for 35 mins, he is covering about 3.9miles in that time. Call that 100 cals/ mile and he uses 390 cals. A little bit out but I'm sure the measurements used aren't precise either!
the bat
9 minute miling for 35 minutes => total distance run = approx 4 miles
If 4 miles burns 500 calories then 1 mile will burn 125 calories
At 12 minutes/mile you will run roughly 3 miles in 35 minutes.
There fore calories burned in 35 minutes = 3x125 = 375 calories
As you're a bit lighter you will probably use slightly less if I can remember my physics correctly. Assuming calories burned is proportional to weight...
=> Calories burned = (11/12)*375 = 344
Hope that helps and I'm sure someone will now come and criticise my calculations...
at least my calcs were roughly right
Teacher: "What's one plus one?"
Johnny: "Two"
Teacher: "That's good"
Johnny: "No, it's perfect"
Tell that to any mathmetician for guaranteed hilarity.
BTW I'm not a mathmetician, just married to one. and I don't get the joke either ....
Sorry - time for me to go back to the Big Brother house now.
Maybe it was
Teacher: "What's three plus three"
I only got grade C in O level maths, that's my excuse.
What is Big Brother? Is it a new UK government initiative?
a^2 - a^2 = a^2 - a^2
These ^2 mean 'squared'. I suppose everybody will agree that this statenment is true. Now rewrite both sides:
a*(a-a) = (a+a)*(a-a)
And divide both sides by the same factor:
a*(a-a)/(a-a) = (a+a)*(a-a)/(a-a)
and you'll get:
a = a+a
which of course is:
a=2*a
Divide both sides by a and you finally see:
1=2
All to do with singularities.
Finally the two years of a maths degree I did prior to starting computing has been of use
doesn`t it or have I got the math wrong its a long time since I got my maths O level(grade c)
SEX is the branch of mathematics where 1+1=3
(a+b)*(a-b)=a^2 -ab +ba - b^2
So the ab and the ba eliminate each other and you're left with a^2-b^2
Now with another a instead of b it gets a bit more confusing as it is zero anyway (so your variation is correct as well)